Question

Question 12 (1 point) The owner of a golf course wants to determine if his golf...

Question 12 (1 point)

The owner of a golf course wants to determine if his golf course is more difficult than the one his friend owns. He has 9 golfers play a round of 18 holes on his golf course and records their scores. Later that week, he has the same 9 golfers play a round of golf on his friend's course and records their scores again. The average difference in the scores (treated as the scores on his course - the scores on his friend's course) is 5.394 and the standard deviation of the differences is 11.7418. Calculate a 90% confidence interval to estimate the average difference in scores between the two courses.

Question 12 options:

1)

(3.5345, 7.2535)

2)

(1.4801, 9.3079)

3)

(1.8841, 12.6721)

4)

(-1.7807, 12.5687)

5)

(-1.8841, 12.6721)

Question 13 (1 point)

A new drug to treat high cholesterol is being tested by pharmaceutical company. The cholesterol levels for 38 patients were recorded before administering the drug and after. The 99% confidence interval for the true mean difference in total cholesterol levels (after - before) was (-48.54, -3.06). Which of the following is the appropriate conclusion?

Question 13 options:

1)

We are 99% confident that the average difference in cholesterol levels is positive, with the higher cholesterol levels being before the drug regimen.

2)

We are 99% confident that the average difference in cholesterol levels is positive, with the higher cholesterol levels being after the drug regimen.

3)

We are 99% confident that the average difference in cholesterol levels is negative, with the higher cholesterol levels being after the drug regimen.

4)

There is not a significant difference in average cholesterol levels before and after the drug.

5)

We are 99% confident that the average difference in cholesterol levels is negative, with the higher cholesterol levels being before the drug regimen.

Question 14 (1 point)

Automobile manufacturers are interested in the difference in reaction times for drivers reacting to traditional incandescent lights and to LED lights. A sample of 22 drivers are told to press a button as soon as they see a light flash in front of them and the reaction time was measured in milliseconds. Each driver was shown each type of light. The average difference in reaction times (traditional - LED) is 0.5 ms with a standard deviation of 7.39 ms. A 90% confidence interval for the average difference between the two reaction times was (-2.21, 3.21). Which of the following is the best interpretation?

Question 14 options:

1)

The proportion of all drivers that had a difference in reaction times between the two lights is 90%.

2)

We are certain the average difference in reaction times between the two light types for all drivers is between -2.21 and 3.21.

3)

We are 90% confident that the average difference in reaction time between the two light types for all drivers is between -2.21 and 3.21.

4)

We are 90% confident that the difference between the average reaction time for LED lights and the average reaction time for traditional lights is between -2.21 and 3.21.

5)

We are 90% confident that the average difference in the reaction times of the drivers sampled is between -2.21 and 3.21.

Homework Answers

Answer #1

12)

sample mean 'x̄= 5.394
sample size   n= 9.00
sample std deviation s= 11.742
std error 'sx=s/√n= 3.9139
for 90% CI; and 8 df, value of t= 1.860
margin of error E=t*std error    = 7.28
lower bound=sample mean-E = -1.89
Upper bound=sample mean+E = 12.67

correct option is:

5) (-1.8841, 12.672 )

13)

Correct option is (5)

We are 99% confident that the average difference in cholesterol levels is negative, with the higher cholesterol levels being before the drug regimen
14)

option 3) is correct

We are 90% confident that the average difference in reaction time between the two light types for all drivers is between -2.21 and 3.21.

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
PART A) The owner of a golf course wants to determine if his golf course is...
PART A) The owner of a golf course wants to determine if his golf course is more difficult than the one his friend owns. He has 25 golfers play a round of 18 holes on his golf course and records their scores. Later that week, he has the same 25 golfers play a round of golf on his friend's course and records their scores again. The average difference in the scores (treated as the scores on his course - the...
The owner of a golf course wants to determine if his golf course is more difficult...
The owner of a golf course wants to determine if his golf course is more difficult than the one his friend owns. He has 29 golfers play a round of 18 holes on his golf course and records their scores. Later that week, he has the same 29 golfers play a round of golf on his friend's course and records their scores again. The average difference in the scores (treated as the scores on his course - the scores on...
The owner of a local golf course wants to determine the average age of the golfers...
The owner of a local golf course wants to determine the average age of the golfers that play on the course in relation to the average age in the area. According to the most recent census, the town has an average age of 23.44. In a random sample of 26 golfers that visited his course, the sample mean was 30.63 and the standard deviation was 8.771. Using this information, the owner calculated the confidence interval of (25.84, 35.42) with a...
Automobile manufacturers are interested in the difference in reaction times for drivers reacting to traditional incandescent...
Automobile manufacturers are interested in the difference in reaction times for drivers reacting to traditional incandescent lights and to LED lights. A sample of 19 drivers are told to press a button as soon as they see a light flash in front of them and the reaction time was measured in milliseconds. Each driver was shown each type of light. A 90% confidence interval for the average difference between the two reaction times (traditional - LED) was (-306.28, -50.17). Which...
Researchers in the corporate office of an airline wonder if there is a significant difference between...
Researchers in the corporate office of an airline wonder if there is a significant difference between the cost of a flight on Priceline.com vs. the airline's own website. A random sample of 15 flights were tracked on Priceline and the airline's website and the 90% confidence interval for the mean difference in price (Priceline - Airline Site) was (-64.52, 32.5). Which of the following is the appropriate conclusion? Question 3 options: 1) There is no significant difference between the average...
****PLEASE ANSWER ALL QUESTIONS**** Question 7 (1 point) The owner of a local golf course wants...
****PLEASE ANSWER ALL QUESTIONS**** Question 7 (1 point) The owner of a local golf course wants to determine the average age of the golfers that play on the course in relation to the average age in the area. According to the most recent census, the town has an average age of 38.58. In a random sample of 20 golfers that visited his course, the sample mean was 36.61 and the standard deviation was 7.505. Using this information, the owner calculated...
PART I The owner of a local golf course wanted to determine the average age (in...
PART I The owner of a local golf course wanted to determine the average age (in years) of the golfers that played on the course. In a random sample of 27 golfers that visited his course, the sample mean was 47 years old and the standard deviation was 5.11 years. Using this information, the owner calculated the confidence interval of (45.3, 48.7) with a confidence level of 90% for the average age. Which of the following is an appropriate interpretation...
The owner of a local golf course wants to estimate the difference between the average ages...
The owner of a local golf course wants to estimate the difference between the average ages of males and females that play on the golf course. He randomly samples 25 men and 28 women that play on his course. He finds the average age of the men to be 36.105 with a standard deviation of 5.507. The average age of the women was 48.973 with a standard deviation of 5.62. He uses this information to calculate a 90% confidence interval...
The owner of a local golf course wants to estimate the difference between the average ages...
The owner of a local golf course wants to estimate the difference between the average ages of males and females that play on the golf course. He randomly samples 30 men and 26 women that play on his course. He finds the average age of the men to be 49.844 with a standard deviation of 5.208. The average age of the women was 35.237 with a standard deviation of 5.573. He uses this information to calculate a 95% confidence interval...
The owner of a local golf course wants to estimate the difference between the average ages...
The owner of a local golf course wants to estimate the difference between the average ages of males and females that play on the golf course. He randomly samples 12 men and 10 women that play on his course. He finds the average age of the men to be 30.81 with a standard deviation of 5.071. The average age of the women was 46.19 with a standard deviation of 11.982. Construct a 95% confidence interval to estimate the difference of...