Compute the probability that there are 2 or fewer defective chips among the 30 chips sampled
Let X be the number of defective memory chips.
Then X ~ Binomial(30,0.01)
Using the above formula we have:
X | P(X=x) |
0 | 0.73970037 |
1 | 0.22415163 |
2 | 0.03283029 |
3 | 0.00309511 |
4 | 0.00021103 |
5 | 0.00001108 |
6 | 0.00000047 |
7 | 0.00000002 |
8 | 0.00000000 |
9 | 0.00000000 |
10 | 0.00000000 |
11 | 0.00000000 |
12 | 0.00000000 |
13 | 0.00000000 |
14 | 0.00000000 |
15 | 0.00000000 |
16 | 0.00000000 |
17 | 0.00000000 |
18 | 0.00000000 |
19 | 0.00000000 |
20 | 0.00000000 |
21 | 0.00000000 |
22 | 0.00000000 |
23 | 0.00000000 |
24 | 0.00000000 |
25 | 0.00000000 |
26 | 0.00000000 |
27 | 0.00000000 |
28 | 0.00000000 |
29 | 0.00000000 |
30 | 0.00000000 |
(a)
We need to find P(X=0)
(b)
We need to find P(X>=1)
(c)
We need to find P(X<=2)
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