Question

In an simple random sample of 200 college students, 114 said that they usually speed on...

In an simple random sample of 200 college students, 114 said that they usually speed on interstate highways by 10 mph or more. Give a 95% confidence interval for the corresponding proportion for all college students. a: (0.5014,0.6455) b: (0.5431,0.6386) c: (0.3567,0.4533) d: (0.5014,0.6386)

Math   Statistics-And-Probability   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

We will calculate the 95% confidence interval by using the tabulated value of z at 5% level of significance.

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
In a simple random sample of 500 freshman students, 276 of them live on campus. You...
In a simple random sample of 500 freshman students, 276 of them live on campus. You want to claim that majority of college freshman students in US live on campus. A) Are the assumptions for making a 95% confidence interval for the true proportion of all college freshman students in the United States who live on campus satisfied? yes/no? B) What is the sample proportion? C.) A 95% confidence interval for the actual proportion of college freshman students in the...
Ages of students: A simple random sample of 100 U.S. college students had a mean age...
Ages of students: A simple random sample of 100 U.S. college students had a mean age of 22.68 years. Assume the population standard deviation is σ = 4.74 years. Construct a 99% confidence interval for the mean age of U.S. college students. The answer I posted my instructor says it is wrong. I came up with 21.45 to 23.91 a 99% confidence interval for the mean of the U.S college students She said the z procedures are needed. Thanks.
Based on a simple random sample of 1440 college students, a 97% confidence interval for the...
Based on a simple random sample of 1440 college students, a 97% confidence interval for the percentage of students who receive financial aid is reported as 82.99% ±± 2.5%. Which of the following is/are correct interpretation(s) of this confidence interval?There may be more than one correct answer; you must check all correct answers in order to get credit for this problem. A. If we select an individual from the population, there is a 97% probability that this individual is one...
Exhibit E Suppose a simple random sample of 150 students to study the proportion of students...
Exhibit E Suppose a simple random sample of 150 students to study the proportion of students who live in dormitories indicates a sample proportion of 0.35. Refer to Exhibit E. To construct a 95% confidence interval for the population proportion, p, the margin of error is:
Suppose a random sample of 50 college students is asked if they regularly eat breakfast. A...
Suppose a random sample of 50 college students is asked if they regularly eat breakfast. A 95% confidence interval for the proportion of all students that regularly eat breakfast is found to be 0.69 to 0.91. If a 90% confidence interval was calculated instead, how would it differ from the 95% confidence interval? The 90% confidence interval would be wider. The 90% confidence interval would be narrower. The 90% confidence interval would have the same width as the 95% confidence...
1.) Suppose that 45% of students have taken an online course. A random sample of 200...
1.) Suppose that 45% of students have taken an online course. A random sample of 200 students is taken, of which 100 have taken an online course. A.) What is the probability of obtaining a sample proportion this high or higher? B.) There is some thought that the proportion taking online courses is no longer 45%. Based on the random sample, construct a 95% confidence interval for the proportion of students who have taken an online course. C.) Compute the...
1. In a random sample of 200 college graduated, 42 said they think a college degree...
1. In a random sample of 200 college graduated, 42 said they think a college degree is not worth the cost. Test to see if this sample provides significant evidence that the population proportion of college graduated who believe a college degree is not worth the cost is different from 25%. Use a 5 a. b. Calculate the observed sample statistic: Calculate the z-scores for this sample statistic: z= ________ c. Use Statkey to find the p-value for this test:...
Most musicians have different popularities among various age groupings. In a random sample of 200 high...
Most musicians have different popularities among various age groupings. In a random sample of 200 high school students, 163 said they liked Beyoncé or her work. In a random sampling of 200 adults aged 30 to 40, 128 of them said they liked Beyoncé or her work. Write down the formula needed in order to create a 95% confidence interval: Construct a 95% confidence interval for the difference in the proportion of students that like Beyonce or her work and...
1.      A questionnaire of spending habits was given to a random sample of college students. Each...
1.      A questionnaire of spending habits was given to a random sample of college students. Each student was asked to record and report the amount of money they spent on books and school supplies in a semester. The amount of money spent on books and school supplies is said to follow normal distribution. The sample of 85 students resulted in an average of $850.   a)     What are the simple conditions necessary for the confidence interval to be valid? b)     Find...
3. A random sample of 78 students was interviewed, and 59 students said that they would...
3. A random sample of 78 students was interviewed, and 59 students said that they would vote for Jennifer McNamara as student body president. a.Let p represent the proportion of all students at this college who will vote for Jennifer. Find a point estimate for p. Round your answer to the nearest hundredth. b.Find a 90% confidence interval for p. Round your answer to the nearest hundredth and THEN change them to a percentage. c.Interpret the meaning of the confidence...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT