Question

Suppose we took samples of employees with 30 employees in each sample. If the average satisfaction...

Suppose we took samples of employees with 30 employees in each sample. If the average satisfaction level is .614 with a standard deviation of .254.

  1. What would be the mean of the sampling distribution?
  2. What is the standard deviation of the sampling distribution
Math   Statistics-And-Probability   
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Answer #1

Solution :

Given that,

mean = = 0.614

standard deviation = = 0.254

n = 30

a) =   = 0.614

= / n = 0.254 / 30 = 0.046

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