Question

A group of 51 randomly selected students have a mean score of 29.5 with a sample...

A group of 51 randomly selected students have a mean score of 29.5 with a sample standard deviation of 5.2 on a placement test. What is the 95% confidence interval for the
mean score, μ, of all students taking the test?

Critical error=

Margin of error=

confidence interval=

Homework Answers

Answer #1

# critical error= 5.2/√51 = 0.7281

# margin of error= 2.009* 0.7281= 1.4628

# c.i= ( 28.037,30.963)

please like

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
A sample of 14 randomly selected students have a sample mean score of 27.6 with a...
A sample of 14 randomly selected students have a sample mean score of 27.6 with a sample standard deviation of 5.1 on a placement test. Construct a 95% confidence interval for the mean score, !, of all students taking the test.
16 students were randomly selected from a large group of students taking a certain calculus test....
16 students were randomly selected from a large group of students taking a certain calculus test. The mean score for the students in the sample was 86 and the standard deviation was 1.3. Assume that the scores are normally distributed. Construct a 98% confidence interval for the mean score, μ, of all students taking the test. Round your answer to two decimal places.
A sample of 25 randomly selected students has a mean test score of 81.5 with a...
A sample of 25 randomly selected students has a mean test score of 81.5 with a standard deviation of 10.2. Assuming that the population has a normal distribution, use this sample data to construct a 95% confidence interval for the population mean μ of all test scores. A. (77.29, 85.71) B. (56.12, 78.34) C. (87.12, 98.32) D. (66.35, 69.89)
16 students were randomly selected from a large group of students taking a certain calculus test....
16 students were randomly selected from a large group of students taking a certain calculus test. The mean score for the students in the sample was 86 and the standard deviation was 1.2. Assume that the scores are normally distributed. Construct a 98% confidence interval for the mean score, μ, of all students taking the test. Round your answer to two decimal places. a- (85.30 , 86.70) b- (85.22 , 86.78) c- (85.36 , 86.64) d- (85.28 , 86.72)
thirty-one randomly selected students scores on the test in MTH 243 were recorded. This sample had...
thirty-one randomly selected students scores on the test in MTH 243 were recorded. This sample had a mean of 73 and a standard deviation of 8.4. Construct a 98% confidence interval for the mean score of all students MTH 243 test score. (round all values to three decimal places) Does this sample satisfy the conditions for constructing a confidence interval? Select an answer Yes No Why do you keep asking these questions of me? What critical value is appropriate for...
Based on a sample of size 49, a 95% confidence interval for the mean score of...
Based on a sample of size 49, a 95% confidence interval for the mean score of all students, μ, on an aptitude test is from 59.2 to 64.8. Find the margin of error. Group of answer choices A) 2.8 B) 0.05 C) 0.78 D) There is not enough information to find the margin of error. E) 5.6
Thirty randomly selected students took the calculus final. If the sample mean was 77 and the...
Thirty randomly selected students took the calculus final. If the sample mean was 77 and the standard deviation was 11.9, construct a 99% confidence interval for the mean score of all students. Round your answer in 2 decimal places
A survey of 25 randomly selected customers had the mean 33.04 years and the standard deviation...
A survey of 25 randomly selected customers had the mean 33.04 years and the standard deviation 10.45 years. What is the standard error of the mean? How would the standard error change if the sample size had been             400 instead of 25? (Assume that the sample standard deviation didn't change.) Find the degrees of freedom for n=60. Find the t critical value for n=60 for 90% CI for mean. A survey of 25 randomly selected customers had the mean...
A survey of 25 randomly selected customers found that their average age was 31.84 years with...
A survey of 25 randomly selected customers found that their average age was 31.84 years with a standard deviation of 9.84 years. What is the standard error of the mean? How would the standard error have changed if the sample size had been 100 instead of 25 (assuming that the mean and standard deviations were the same)? How many degrees of freedom would the t-statistic have for this set of data? What would the critical value t* be for a...
3. A sample of 30 randomly selected TV sets has a repair cost mean of $...
3. A sample of 30 randomly selected TV sets has a repair cost mean of $ 356.25, with a standard deviation of $ $19.75. Find the margin of error E for a 95% confidence interval.
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT