Now imagine that the votes for each party shown in Table 1 are the same, but that they are for a district where 10 candidates are elected using a highest averages system to allocate seats. This means that the votes parties receive are divided by a series of numbers to give quotients. This country uses the d’Hondt method (the divisors are 1, 2, 3, 4,…). Seats are allocated to the party with the largest quotient, then the second largest, then the third largest… until all of the seats have been allocated.
Table 2
Party A |
Party B |
Party C |
Party D |
Party E |
Party F |
Total |
|
Votes |
38000 |
20800 |
19300 |
14500 |
5750 |
1650 |
100,000 |
1 |
38000 |
20800 |
19300 |
14500 |
5750 |
1650 |
|
2 |
19000 |
10400 |
9650 |
7250 |
2875 |
825 |
|
3 |
12666.7 |
6933.3 |
6433.3 |
4833.3 |
1916.7 |
550 |
|
4 |
9500 |
5200 |
4825 |
3625 |
1437.5 |
412.5 |
|
5 |
7600 |
4160 |
3860 |
2900 |
1150 |
330 |
|
Total Seats |
10 |
1. In the district described in Table 2, how many total seats does Party A win?
2. How many total seats does Party E win?
Party A |
Party B |
Party C |
Party D |
Party E |
Party F |
||
Votes |
38000 |
20800 |
19300 |
14500 |
5750 |
1650 |
100,000 |
1 |
38000 |
20800 |
19300 |
14500 |
5750 |
1650 |
|
2 |
19000 |
10400 |
9650 |
7250 |
2875 |
825 |
|
3 |
12666.7 |
6933.3 |
6433.3 |
4833.3 |
1916.7 |
550 |
|
4 |
9500 |
5200 |
4825 |
3625 |
1437.5 |
412.5 |
|
5 |
7600 |
4160 |
3860 |
2900 |
1150 |
330 |
|
Total Seats |
10 |
The top 10 values in the table are marked in bold. These represent the number of seats won by a party.
1. Party A won 5 seats
2. Party E won 0 seats
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