Problem: Using the following data, test the question that an equal number of boys (code=1) and girls (code=2) participate in soccer at the elementary level at the .01 level of significance. Use SPSS and compute the exact probability of the chi-square value. What’s your conclusion? Make sure that you identify the null and research hypotheses, the DV and IV, the p-value, whether you reject or accept the null hypothesis and what this means.
Ge |
nder |
||
Boys = 1 |
Girls = 2 |
||
45 |
55 |
SOLUTION:
From given data,
Problem: Using the following data, test the question that an equal number of boys (code=1) and girls (code=2) participate in soccer at the elementary level at the .01 level of significance. Use SPSS and compute the exact probability of the chi-square value. What’s your conclusion? Make sure that you identify the null and research hypotheses, the DV and IV, the p-value, whether you reject or accept the null hypothesis and what this means.
Launch SPSS
Click on Variable view.
Enter variable name "Gender" and press enter.
Make decimals 0.
Click on values, one small popup window will appear.
In that small window, enter value=1, Label=Boys and click on Add.
Now enter value=2, Label=Girls and click Add again.
Now click OK.
Now enter second variable name "Frequency" and press enter.
Make Decimals 0.
The variable view will look like this
Now click on Data View and enter data as shown below:
Now click on Data->Weight Cases.
Select "Weight cases by" and move "Frequency" to text box and click OK.
Now Click on Analyze->Non-parametric tests->Legacy dialogs->Chi-Square Test.
Fill the box as shown below:
Now click OK.
The output is
shown below:
Chi-square Test
Frequencies
Gender | |||
Observed N | Expected N | Residual | |
Boys | 45 | 50.0 | -5.0 |
Girls | 55 | 50.0 | 5.0 |
Total | 100 |
Test Statistics
Gender | |
Chi-Square | 1.0003 |
df | 1 |
Asymp.Sig | .317 |
a. 0 cells (.0%) have frequencies less than 5.
The minimum expected cell frequency is 50.0.
Null hypothesis: Gender is uniformly distributed
Research hypothesis: Gender is not uniformly distributed
The independent variable is Gender.
From above output, the p-value = 0.317
Since p-value is greater than 0.01 level of significance, fail to reject the null hypothesis. We can conclude that an equal number of boys and girls participate in soccer at the elementary level at the .01 level of significance
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