Certain type of light bulbs has a mean lifespan of 21 hours and a standard deviation of 2.25 hours. What is the probability that the total lifespan of 200 lightbulbs is less than 4100 hours?
= 21
= 2.25
n = 200
SE = /
= 2.25/
= 0.1591
= 4100/200 = 20.5
To find P(20.5):
Z = (20.5 - 21)/0.1591
= - 3.1427
By Technology, Cumulative Area Under Standard Normal Curve = 0.00083699
So,
Answer is:
0.00083699
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