If you want to be 95% confident of estimating the population mean to within a sampling error of plus or minus 6 and the standard deviation is assumed to be 20, what sample size is required?
The sample size required is __
(Round up to the nearest integer.)
Solution
standard deviation = =20
Margin of error = E =+/- 6
At 95% confidence level the z is ,
= 1 - 95% = 1 - 0.95 = 0.05
/ 2 = 0.05 / 2 = 0.025
Z/2 = Z0.025 = 1.96 ( Using z table ( see the 0.025 value in standard normal (z) table corresponding z value is 1.96 )
sample size = n = [Z/2* / E] 2
n = ( 1.96*20 /6 )2
n =42.68
Sample size = n =43
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