Of all the people applying for a certain job, 80%are qualified and 20% are not. The personnel manager claims that she approves qualified people 80% of the time; she approves unqualified people 10% of the time. Find the probability that a person is qualified if he or she was approved by the manager
The probability is..?
We are given here that:
P( qualified ) = 0.8,
P( not qualified ) = 0.2
Also, P( approve | qualified ) = 0.8 and P( approve | not qualified ) = 0.1
Using law of total probability, we get here:
P( approve) = P( approve | qualified )P( qualified ) + P( approve |
not qualified )P( not qualified )
P( approve) = 0.8*0.8 + 0.2*0.1 = 0.64 + 0.02 = 0.66
Given that the the person is approved by manager, probability that the person is qualified is computed using Bayes theorem here as:
P( qualified | approve ) = P( approve | qualified )P( qualified ) / P( approve)
= 0.64 /0.66
= 0.9697
Therefore 0.9697 is the required probability here.
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