Packets arrive at a certain node on the university’s intranet at 10 packets per minute, on average. Assume packet arrivals meet the assumptions of a Poisson process.
Let X be the random variable denoting Packets arrive at a certain node on the university’s intranet.
So X ~ Poisson (10) per minute
1) the probability that exactly 15 packets arrive in the next 2 minutes
X ~ Poisson (20) per 2 minute
= 0.052
2) the probability that more than 60 packets arrive in the next 5 minutes
X ~ Poisson (50) per 5 minute
3)the probability that the next packet will arrive in within 15 seconds.
X ~ Poisson (2.5) per 15 seconds
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