Question

The results of a survey of 800 married couples and the number of children they had...

The results of a survey of 800 married couples and the number of children they had is shown below

Number of Children Probability
0 0.1
1 0.3
2 0.4
3

0.2

(1) What is the standard deviation of the number of children in a family?

    a.  
0.92

    b.  
0.90

    c.  
0.81

    d.  
0.85

Homework Answers

Answer #1

The below table helps us in finding the standard deviation

Number of Children (x) Probability P(x) x * P(x) X2 X2 * P(x)
0 0.1 0 0 0
1 0.3 0.3 1 0.3
2 0.4 0.8 4 1.6
3 0.2 0.6 9 1.8
x * P(x) = 1.7 x2 * P(x) = 3.7

Mean = x * P(x)

= 1.7

Standard Deviation = [ x2 * P(x) ] - 2

= 3.7 - 1.72

= 3.7 - 2.89

= 0.81

= 0.9

So Answer is Option B

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
The results of a survey of 800 married couples and the number of children they had...
The results of a survey of 800 married couples and the number of children they had is shown below. Number of Children Probability 0 .050 1 .125 2 .600 3 .150 4 .050 5 .025 If a couple is selected at random, what is the probability that the couple will have a. less than four children? b. more than two children? c. either two or three children?
A survey asked a group of medical doctors how many children they had fathered. The results...
A survey asked a group of medical doctors how many children they had fathered. The results are summarized by this ungrouped frequency distribution. Number of Children 0 1 2 3 4 6 Number of Doctors 18 14 24 14 6 3 (a) Calculate the sample mean for the number of children the doctors had fathered. (Give your answer correct to two decimal places.) (b) Calculate the variance for the number of children the doctors had fathered using the short-cut formula...
In a survey 46,281 women were asked how many children they had. The results were as...
In a survey 46,281 women were asked how many children they had. The results were as follows. Number of children: 0 1 2     3      4 5   6 7 8 or more Number of women 12,574 7,493. 11.282 7,124 3,778 1,811  924 523 772 a) P(sampled woman has exactly 4 children)? _______________________ b) P(Sampled woman has more than 3 children)? ___________________ c) Assume this is a simple random sample of U.S. women. Use the Empirical Method to estimate the probability that...
Let X have a normal distribution with mean 6 and standard deviation 3 1) Compute the...
Let X have a normal distribution with mean 6 and standard deviation 3 1) Compute the probability that X>8.7 . 0-0.1 0.1-0.2 0.2-0.3 0.3-0.4 0.4-0.5 0.5-0.6 0.6-0.7 0.7-0.8 0.8-0.9 0.9-1 2) Compute the probability that X<0 . 0-0.1 0.1-0.2 0.2-0.3 0.3-0.4 0.4-0.5 0.5-0.6 0.6-0.7 0.7-0.8 0.8-0.9 0.9-1 3) Compute the probability that |X-6|>1.9 . 0-0.1 0.1-0.2 0.2-0.3 0.3-0.4 0.4-0.5 0.5-0.6 0.6-0.7 0.7-0.8 0.8-0.9 0.9-1
In a survey of 390 childless married couples who were asked if they plan to have...
In a survey of 390 childless married couples who were asked if they plan to have children in the next 5 years, 35% of the men and 30% of the women responded "Yes". Based on this survey, can it be concluded that there is a difference in the proportion of men ( p1 ) and women ( p2 ) responding "Yes"? Use a significance level of α=0.1 for the test. Step 1 of 5: State the null and alternative hypotheses...
The number of students using the School Bus per day is found in the distribution below....
The number of students using the School Bus per day is found in the distribution below.      X 15 25 10 12     P(X) 0.3 0.4 0.2 0.1 Find the mean , variance, and the standard deviation for this probability distribution.
Standard deviation for fruits and vegetables The following table gives the distribution of the number of...
Standard deviation for fruits and vegetables The following table gives the distribution of the number of servings of fruits and vegetables consumed per day in a population. Number of servings X 0 1 2 3 4 5 Probability 0.3 0.1 0.1 0.2 0.2 0.1 Find the standard deviation for the distribution of the number of servings of fruits and vegetables. (report to 1 decimal place)
A survey recorded the number of children 18 years old or younger who lived in 200...
A survey recorded the number of children 18 years old or younger who lived in 200 households. The accompanying table shows the results. a. Determine the mean number of children per household. b. Determine the standard deviation for the number of children per household. Number_of_Children   Number_of_Families 0 89 1 38 2 41 3 22 4 8 5 2
A survey asked the question​ "What do you think is the ideal number of children for...
A survey asked the question​ "What do you think is the ideal number of children for a family to​ have?" 411 males and 343 females answered the survey and responded with a numeric response from 0 to 6. The 411 males who responded had a mean of 3.18​, and standard deviation of 1.6​, where the 343 females had a median of​ 2, a mean of 3.27 and a standard deviation of 1.69. The​ 95% confidence interval for the female population...
The probability model below describes the number of repair calls that an appliance repair shop may...
The probability model below describes the number of repair calls that an appliance repair shop may receive during an hour. Repair Calls 0 1 2 3 Probability 0.2 0.3 0.4 0.1 On​ average, the shop receives 1.4 calls an​ hour, with a standard deviation of 0.92 calls. Suppose that the appliance shop plans a 7​-hour day. a) Find the mean and standard deviation of the number of repair calls they should expect in a day. The mean number of repair...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT