Suppose Z1, Z2, Z3, and Z4 are i.i.d. standard normal random variables. Calculate the following:
(a) P(Z1 +Z2 +Z3 +Z4 >3)
(b) P(Z12 +Z2 +Z32 +Z42 >7.78)
(c) P(Z1/?Z2 +Z32 +Z42 <1.36)
Answer:
Given that,
Suppose Z1, Z2, Z3, and Z4 are i.i.d. standard normal random variables.
(a).
P(Z1 +Z2 +Z3 +Z4 >3):
X =Z1+Z2+Z3+Z4 will be normal have normal distribution with
Mean =0 and
Standard deviation = =2
Probability =P(X>3)
=P(Z>(3-0)/2)
=P(Z>1.5)
=1-P(Z<1.5)
=1-0.9332
=0.0668
(b).
P(Z12+Z22+Z32+Z42 >7.78):
X =Z12+Z22+Z32+Z42 follow chi square distribution with 4 degree of freedom
P(X >7.78)=0.10
(c).
:
P(Z1/√(Z22+Z32+Z42 / 3 )) follows t distribution with 3 degree of freedom
P(X /√3 <1.36)
=P(X<2.356)
=0.95
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