Question

Johon, a call centre consultant, knows that, based on his past performances, he has a 40% chance of making a sale when calling on customer. One morning she has call 8 clients. What is her probability of making more than 2 sales (round off to 3 decimal places)?

Answer 1

Given a call centre consultant, knows that, based on his past performances, he has a 40% chance of making a sale when calling on customer, thus the p = 0.40.

One morning she has call 8 clients. Now the probability of making more than 2 sales P(X>2) is calculated as:

=> 1- {P(X = 2) + P(X = 1) + P( X=0)}

Now the probability assuming binomial distribution is calculated as:

Thus the probability at X = 0 is computed as:

P( X = 0) = 0.01679616

and at X = 1

P(X = 1) = 0.08957952

and at X = 2

P(X = 2) = 0.20901888

Thus the probability P( X >2) is computed as:

=> 1- {0.01679616+0.08957952+0.20901888}

=1-0.31539456

= 0.685 rounded to three decimals.