A fashion designer wants to know how many new dresses women buy each year. She thinks the mean is 6.6 dresses per year. Assume a previous study found the variance to be 4. How large of a sample would be required in order to estimate the mean number of dresses bought per woman at the 98% confidence level with an error of at most 0.09 dresses?
Solution :
Given that,
variance = 2 = 4
standard deviation = = 2
margin of error = E = 0.09
At 98% confidence level the z is ,
= 1 - 98% = 1 - 0.98 = 0.02
/ 2 = 0.02 / 2 = 0.01
Z/2 = Z0.01 = 2.33
Sample size = n = ((Z/2 * ) / E)2
= ((2.33 * 2) /0.09 )2
=2680.93 = 2681
Sample size = 2681
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