Question

Use the given data to find the minimum sample size required to estimate a population proportion or percentage. Margin of error: nine percentage points; confidence level 90%; from a prior study, p hat is estimated by the decimal equivalent of 46%

Answer #1

Solution :

Given that,

= 46% = 0.46

1 - = 1 - 0.46 = 0.54

Margin of error = E = 9% = 0.09

At 90% confidence level the z is ,

= 1 - 90% = 1 - 0.90 = 0.10

/ 2 = 0.10 / 2 = 0.05

Z_{/2}
= Z_{0.05} = 1.645

Sample size = ( Z_{/2} /
E)^{2} * * (1 - )

= (1.645 / 0.09)^{2} * 0.46 * 0.54

= 82.98

Sample size = n = 83

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nine percentage points; confidence level 90 %; from a prior study,
ModifyingAbove p with caret is estimated by the decimal equivalent
of 56 % nequals nothing (Round up to the nearest integer.)

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of error 3 percentage points confidence level 90% from a prior
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Margin of error: five percentage points; confidence level
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Margin of error: 0.008; confidence level: 98%;
ModifyingAbove p with caret
and
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unknown

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