X and Y ar i.i.d. exponential random variables with mean = 2. Let Z = X + Y. The probability that Z is less than or equal to 3 is:
Answer :
Given data is :
There are two random variables X and Y.
Mean(X + Y) = = 4
Var(X + Y) = 8
then standard deviation = =
=
= 2.83
= 2.83
Now given condition is : P(Z <= 3)
Where Z = x+y = 3
P(x+y <= 3) =
= (3 - 4) / 2.83
= - 1 / 2.83
= - 0.35
From z table values,
P(x+y <= 3) = P(Z <= -0.35) = 0.3632
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