Question

A coin is tossed 6 times. What is the probability that the number of heads obtained will be between 2 and 3 inclusive? Express your answer as a fraction or a decimal number rounded to four decimal places.

PLEASE DON'T ANSWER UNLESS YOU ARE CONFIDENT YOU KNOW THE SOLUTION.

Answer 1

Answer :

Given that :

No.of times coin tossed n = 6

and p = 1 / 2 = 0.5

q = 1 - p = 1 - 0.5 = 0.5

The probability that the number of heads obtained will be between 2 and 3 inclusive.

Formula to calculate P(X = x) is ,

P(X = x) =

P(X = 0) =

P(X = 1) =

P(X = 4) =

P(X = 5) =

P(X = 6) =

therefore,

Probability of no.of heads = 1 - P(X = 0) - P(X = 1) - P(X = 4) - P(X = 5) - P(X = 6)

= 1 - 0.0156 - 0.0939 - 0.2343 - 0.0939 - 0.0156

= 0.5467

Probability of no.of heads between 2 and 3 = 0.5467