Question

Let X and Y be independent discrete random variables with pmf’s: x 1 2 3 y...

Let X and Y be independent discrete random variables with pmf’s:

x

1

2

3

y

2

4

6

p(x)
0.2

0.2

0.6

p(y)
0.3

0.1

0.6



What is the probability that X + Y = 7
Math   Statistics-And-Probability   
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Homework Answers

Answer #1

P(X + Y = 7) = P(X = 1, Y = 6) + P(X = 3, Y = 4)

                     = P(X = 1) * P(Y = 6) + P(X = 3) * P(Y = 4)

                     = 0.2 * 0.6 + 0.6 * 0.1

                     = 0.18

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