Construct the indicated confidence interval for the population mean mu? using a? t-distribution.
c=0.95, x =110,s= 10, n=27
The confidence interval is
?(Round to the nearest tenth as? needed.)
Solution :
Given that,
= 110
s = 10
n = 27
c = 0.95
Degrees of freedom = df = n - 1 = 27 - 1 = 26
= 1 - 0.95 = 0.05
/ 2 = 0.05 / 2 = 0.025
t /2,df = t0.025,26 = 2.056
Margin of error = E = t/2,df * (s /n)
= 2.056 * (10 / 27) = 3.96
The confidence interval estimate of the population mean is,
- E < < + E
110 - 3.96 < < 110 + 3.96
106.04 < < 113.96
(106, 114 )
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