Question

The average amount of a beverage in randomly selected 16-ounce beverage can is 15.8 ounces with a standard deviation of 0.5 ounces. If a random sample of thirty-six 16-ounce beverage cans are selected, what is the probability that the mean of this sample is less than 15.7 ounces of beverage? Answer: (keep 4 decimal places)

Answer 1

Solution :

Given that ,

mean = = 15.8

standard deviation = = 0.5

n = 36

=   = 15.8

= / n = 0.5/ 36 = 0.083

P( < 15.7) = P(( - ) / < (15.7 - 15.8) / 0.083)

= P(z < -1.20)

Using z table

= 0.1151