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Speeding: On a stretch of Interstate-89, car speed is a normally distributed variable with a mean...

Speeding: On a stretch of Interstate-89, car speed is a normally distributed variable with a mean of 68.3 mph and a standard deviation of 3.5 mph.

You are traveling at 75 mph. Approximately what percentage of cars are traveling faster than you? Enter your answer as a percentage with 1 decimal place.
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Answer #1

The following information has been provided:

μ=68.3, σ=3.5

We need to compute Pr(X≥75). The corresponding z-value needed to be computed is:

Therefore, we get that

The following is obtained graphically:

Please do upvote if you are satisfied! Let me know in the comments if anything is not clear. I will reply ASAP!

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