Kuya is relocating to China to manage a local branch of world news broadcasting station. He needs to decide on which mobile phone providers he should select based on a sample data of monthly charges from various subscribers. He came to you with the data to determine the provider with the lowest charges, on the average. Which provider would you advise Kuya to select?
Mobile | Unicom | Telecom |
62 | 60 | 62 |
55 | 71 | 58 |
69 | 64 | 68 |
58 | 65 | 57 |
56 | 67 | 63 |
63 | 64 | 57 |
63 | 71 | 69 |
63 | 72 | 68 |
64 | 65 | 67 |
64 | 64 | 69 |
64 | 65 | 68 |
64 | 70 | 60 |
57 | 71 | 63 |
61 | 64 | 69 |
59 | 68 | 69 |
57 | 67 | 66 |
57 | 72 | 62 |
53 | 71 | 66 |
51 | 64 | 67 |
62 | 68 | 62 |
59 | 72 | 60 |
71 | 65 | 59 |
59 | 73 | 57 |
58 | 72 | 59 |
68 | 73 | 65 |
The appropriate test for this problem is:
one-way ANOVA |
repeated measurements |
The obtained statistic is:
F = 17.7 |
F = 1.77 |
F = 7,71 |
F = .177 |
The associated p value is:
< .05 |
< .01 |
< .001 |
< .0001 |
Decision is:
reject the null |
retain the null |
Conclusion is:
1)go with Mobile |
2)go with Unicom |
3)a toss up between Mobile and Unicom |
4)no conclusion can be drawn |
applying one way ANOVA on above data:
Groups | Count | Sum | Average | Variance | |
Mobile | 25 | 1517 | 60.68 | 23.47667 | |
Unicom | 25 | 1698 | 67.92 | 13.99333 | |
Telecom | 25 | 1590 | 63.6 | 18.75 | |
ANOVA | |||||
Source of Variation | SS | df | MS | F | P-value |
Between Groups | 663.39 | 2.00 | 331.69 | 17.70 | 0.0000 |
Within Groups | 1349.28 | 72.00 | 18.74 | ||
Total | 2012.67 | 74.00 |
The appropriate test for this problem is- one-way ANOVA
The obtained statistic is: F = 17.7
The associated p value is: < .0001
Decision is: reject the null
Conclusion is: 1)go with Mobile
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