Question

As in the previous problem, a fair coin is flipped 28 times. If X is the number of heads, then the distribution of X can be approximated with a normal distribution, N(14,2.6), where the mean (μ) is 14 and standard deviation (σ) is 2.6. Using this approximation, find the probability of flipping 18 or 19 heads. You may use the portion of the Standard Normal Table below. z1.21.31.41.51.61.71.81.92.02.12.20.000.88490.90320.91920.93320.94520.95540.96410.97130.97720.98210.98610.010.88690.90490.92070.93450.94630.95640.96490.97190.97780.98260.98640.020.88880.90660.92220.93570.94740.95730.96560.97260.97830.98300.98680.030.89070.90820.92360.93700.94840.95820.96640.97320.97880.98340.98710.040.89250.90990.92510.93820.94950.95910.96710.97380.97930.98380.98750.050.89440.91150.92650.93940.95050.95990.96780.97440.97980.98420.98780.060.89620.91310.92790.94060.95150.96080.96860.97500.98030.98460.98810.070.89800.91470.92920.94180.95250.96160.96930.97560.98080.98500.98840.080.89970.91620.93060.94290.95350.96250.96990.97610.98120.98540.98870.090.90150.91770.93190.94410.95450.96330.97060.97670.98170.98570.9890

Answer 1