A group of students estimated the length of one minute without reference to a watch or clock, and the times (seconds) are listed below. Use a 0.10 significance level to test the claim that these times are from a population with a mean equal to 60 seconds. Does it appear that students are reasonably good at estimating one minute?
81 |
91 |
49 |
74 |
48 |
34 |
68 |
70 |
77 |
54 |
71 |
82 |
104 |
99 |
76 |
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Question: Listed below are the lead concentrations in μg/g measured in different traditional medicines. Us...
Listed below are the lead concentrations in μg/g measured in different traditional medicines. Use a 0.01 significance level to test the claim that the mean lead concentration for all such medicines is less than 16 μg/g.
12 2.5 15.5 18 18.5 5 22 10 13 13.5
A group of students estimated the length of one minute without reference to a watch or clock, and the times (seconds) are listed below. Use a 0.10 significance level to test the claim that these times are from a population with a mean equal to 60 seconds. Does it appear that students are reasonably good at estimating one minute?
81 |
91 |
49 |
74 |
48 |
34 |
68 |
70 |
77 |
54 |
71 |
82 |
104 |
99 |
76 |
Assume that a simple random sample has been selected from a normally distributed population and test the given claim. Identify the null and alternativehypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim.
A safety administration conducted crash tests of child booster seats for cars. Listed below are results from those tests, with the measurements given in hic(standard head injury condition units). The safety requirement is that the hic measurement should be less than 1000 hic. Use a 0.05 significance level to test the claim that the sample is from a population with a mean less than 1000 hic. Do the results suggest that all of the child booster seats meet the specifiedrequirement?
719 657 1021 559 516 500
a)
= 0.10
sample size (n) = 15
sample mean = 71.87
sample standard deviation (S) = 19.33
Hypothesis:
Test statistic:
Degrees of Freedom = n-1 = 15-1 = 14
P-value: 0.032 ..............................From t table
Conclusion:
P-value < , i.e. 0.032 < 0.10, That is Reject Ho at 10% level of significance.
b)
= 0.01
sample size (n) = 10
sample mean = 13
sample standard deviation (S) = 6.03
Hypothesis:
Ho: = 16
Ha: < 16
Test statistic:
Degrees of Freedom = n-1 = 10-1 = 9
P-value: 0.075 ........................From t table
Conclusion:
P-value > , i.e. 0.075 < 0.01, That is Fail to Reject Ho at 1% level of significance.
Therefore, there is Not enough evidence to support the claim that the mean lead concentration for all such medicines is less than 16 μg/g.
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