Out of 30 randomly sampled black bears, 8 had missing tags. Test the claim that the proportion of black bears missing tags is different from the population proportion of 34%. Use alpha = 0.05
1) Hypothesis:
H0 : p=0.34
H1: p 0.34
2) n= 30
The sample proportion = p^ = 8/30 = 0.27
(p(1-p)/n) = (0.34*0.66)/30 = 0.0865
Test statistic Z = (p^-p)/(p(1-p)/n)
= (0.27-0.34)/0.0865
Test statistic Z = -0.8092
Now calculate p value for Z test statistic is 0.4179.
P value = 0.4179
3) result : do not reject null hypothesis.
4) conclusion:
The p value (0.4179) is greater than 0.05 level of significance that is do not reject null hypothesis at 5% level of significance.
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