Question

Here are the data for radioactive decay of radioactive sample: Time 1 3 5 7 Log...

Here are the data for radioactive decay of radioactive sample:

Time 1 3 5 7
Log Count 6.36662 5.77194 5.31677 4.76331

The least-squares regression line for these data is

count=6.6077+(−0.26326 ⋅time)count=6.6077+(−0.26326 ⋅time).

Calculate the residuals for the given counts.

Residual is actual value minus predicted value.

(Use decimal notation. Give your answer to five decimal places.)

Residual for case 1 is

Residual for case 2 is

Residual for case 3 is

Residual for case 4 is

Math   Statistics-And-Probability   
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Homework Answers

Answer #1

Residual for case 1 is

 0.02218

Residual for case 2 is

 -0.04598

Residual for case 3 is

 0.02537

Residual for case 4 is

 -0.00157

[ explanation:-

time actual count

predicted count

count=6.6077+(−0.26326 *time).

residual

= actual count-predicted count
1 6.36662 6.6077-(0.26326*1)=6.34444 0.02218
3 5.77194 5.81792 -0.04598
5 5.31677 5.2914 0.02537
7 4.76331 4.76488 -0.00157

]

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