In the Journal of Marketing Research (November 1996),
Gupta studied the extent to which the purchase behavior of
scanner panels is representative of overall brand
preferences. A scanner panel is a sample of households whose
purchase data are recorded when a magnetic identification card is
presented at a store checkout. The table below gives peanut butter
purchase data collected by the A. C. Nielson Company using a panel
of 2,500 households in Sioux Falls, South Dakota. The data were
collected over 102 weeks. The table also gives the market shares
obtained by recording all peanut butter purchases at the same
stores during the same period.
Brand | Size | Number of Purchases by Household Panel | Market Shares |
Jif | 18 oz. | 3,197 | 19.06% |
Jif | 28 | 1,892 | 8.83 |
Jif | 40 | 715 | 4.87 |
Peter Pan | 10 | 4,065 | 18.04 |
Skippy | 18 | 6,222 | 28.28 |
Skippy | 28 | 1,693 | 13.49 |
Skippy | 40 | 1,441 | 7.43 |
Total | 19,225 | ||
Goodness-of-Fit Test | |||||
obs | expected | O – E | (O – E)2/E | % of chisq | |
3,197 | 3,664.285 | -467.285 | 59.590 | 8.99 | |
1,892 | 1,697.568 | 194.432 | 22.269 | 3.36 | |
715 | 936.258 | -221.258 | 52.288 | 7.89 | |
4,065 | 3,468.190 | 596.810 | 102.700 | 15.49 | |
6,222 | 5,436.830 | 785.170 | 113.392 | 17.10 | |
1,693 | 2,593.453 | -900.453 | 312.639 | 47.16 | |
1,441 | 1,428.418 | 12.582 | .111 | .02 | |
19,225 | 19,225.002 | -.002 | 662.989 | 100.01 | |
(a) Show that it is appropriate to carry out a
chi-square goodness of fit test.
Each expected value is ≥
(b) Test to determine whether the purchase
behavior of the panel of 2,500 households is consistent with the
purchase behavior of the population of all peanut butter
purchasers. Assume here that purchase decisions by panel members
are reasonably independent, and set α = .05.
(Round your answers
χ2to
2 decimal places and
χ2.05
to 3 decimal places.)
χ2χ2 statistic | |
χ2.05χ.052 | |
(Click to select)RejectDo not reject H0.
Conclude purchase behavior is (Click to select)not
consistentconsistent.
ev: 11_18_2012
(a) From the data, each expected value is 5, therefore it is appropriate to carry out a chi square goodness of fit test.
___________________________________________________________________
(b) The Hypothesis:
H0: There is no difference in the purchase behaviour of the 2 populations. The data is consistent.
Ha: There is a significant difference in the purchase behaviour of the 2 populations.The data is not considtent.
The Test Statistic: = 662.99
The Critical Value: , df = n - 1 = 6 is 12.592
The Decision: Since > , We Reject H0.
The Conclusion: The data is not consistent.
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