Question

In the Journal of Marketing Research (November 1996), Gupta studied the extent to which the purchase...

In the Journal of Marketing Research (November 1996), Gupta studied the extent to which the purchase behavior of scanner panels is representative of overall brand preferences. A scanner panel is a sample of households whose purchase data are recorded when a magnetic identification card is presented at a store checkout. The table below gives peanut butter purchase data collected by the A. C. Nielson Company using a panel of 2,500 households in Sioux Falls, South Dakota. The data were collected over 102 weeks. The table also gives the market shares obtained by recording all peanut butter purchases at the same stores during the same period.

Brand Size Number of Purchases by Household Panel Market
Shares
Jif 18 oz. 3,197 19.06%
Jif 28 1,892 8.83
Jif 40 715 4.87
Peter Pan 10 4,065 18.04
Skippy 18 6,222 28.28
Skippy 28 1,693 13.49
Skippy 40 1,441 7.43
Total 19,225
Goodness-of-Fit Test
obs expected O – E (O – E)2/E % of chisq
3,197 3,664.285 -467.285 59.590 8.99
1,892 1,697.568 194.432 22.269 3.36
715 936.258 -221.258 52.288 7.89
4,065 3,468.190 596.810 102.700 15.49
6,222 5,436.830 785.170 113.392 17.10
1,693 2,593.453 -900.453 312.639 47.16
1,441 1,428.418 12.582 .111 .02
19,225 19,225.002 -.002 662.989 100.01


(a) Show that it is appropriate to carry out a chi-square goodness of fit test.

Each expected value is ≥               

(b) Test to determine whether the purchase behavior of the panel of 2,500 households is consistent with the purchase behavior of the population of all peanut butter purchasers. Assume here that purchase decisions by panel members are reasonably independent, and set α = .05. (Round your answers χ2to 2 decimal places and χ2.05 to 3 decimal places.)

χ2χ2 statistic
χ2.05χ.052

(Click to select)RejectDo not reject H0. Conclude purchase behavior is (Click to select)not consistentconsistent.
ev: 11_18_2012

Homework Answers

Answer #1

(a) From the data, each expected value is 5, therefore it is appropriate to carry out a chi square goodness of fit test.

___________________________________________________________________

(b) The Hypothesis:

H0: There is no difference in the purchase behaviour of the 2 populations. The data is consistent.

Ha: There is a significant difference in the purchase behaviour of the 2 populations.The data is not considtent.

The Test Statistic: = 662.99

The Critical Value: , df = n - 1 = 6 is 12.592

The Decision: Since > , We Reject H0.

The Conclusion: The data is not consistent.

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