You want to know the percentage of utility companies that earned revenue less than 76 million dollars. If the mean revenue was 90 million dollars and the data has a standard deviation of 18 million, find the percentage. Assume that the distribution is normal. Round your answer to the nearest hundredth.
Solution :
Given, X follows Normal distribution with,
= 90
= 18
Find P(X < 76)
= P[(X - )/ < (76 - )/]
= P[Z < (76 - 90)/18]
= P[Z < -0.778]
= 0.2183 ... ( use z table)
P(X < 76) = 21.83%
Get Answers For Free
Most questions answered within 1 hours.