Question

You want to know the percentage of utility companies that earned revenue less than 76 million...

You want to know the percentage of utility companies that earned revenue less than 76 million dollars. If the mean revenue was 90 million dollars and the data has a standard deviation of 18 million, find the percentage. Assume that the distribution is normal. Round your answer to the nearest hundredth.

Homework Answers

Answer #1

Solution :

Given, X follows Normal distribution with,

   = 90

   = 18

Find P(X < 76)

= P[(X - )/ <  (76 - )/]

= P[Z <  (76 - 90)/18]

= P[Z < -0.778]

= 0.2183 ... ( use z table)

P(X < 76) = 21.83%

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