Question

Five males with an X-linked genetic disorder have one child each. The random variable x is the number of children among the five who inherit the X-linked genetic disorder. Determine whether a probability distribution is given. If a probability distribution is given, find its mean and standard deviation. If a probability distribution is not given, identify the requirements that are not satisfied. |
x |
P(x) |
|||
---|---|---|---|---|---|

0 |
0.0290.029 |
||||

1 |
0.1490.149 |
||||

2 |
0.3220.322 |
||||

3 |
0.3220.322 |
||||

4 |
0.1490.149 |
||||

5 |
0.0290.029 |

Does the table show a probability distribution? Select all that apply.

A.

Yes, the table shows a probability distribution.

B.

No, not every probability is between 0 and 1 inclusive.

C.

No, the random variable x is categorical instead of numerical.

D.

No, the random variable x's number values are not associated with probabilities.

E.

No, the sum of all the probabilities is not equal to 1.

Find the mean of the random variable x. Select the correct choice below and, if necessary, fill in the answer box to complete your choice.

A.

muμequals=

child(ren) (Round to one decimal place as needed.)

B.

The table does not show a probability distribution.

Find the standard deviation of the random variable x. Select the correct choice below and, if necessary, fill in the answer box to complete your choice.

A.

sigmaσequals=

child(ren) (Round to one decimal place as needed.)

B.

The table does not show a probability distribution.

Click to select and enter your answer(s).

Answer #1

a) The sum of all individual probabilities = 0.029 + 0.149 + 0.322 + 0.322 + 0.149 + 0.029 = 1

Option - A) Yes, the table shows a probability distribution.

b) = E(X) = 0 * 0.029 + 1 * 0.149 + 2 * 0.322 + 3 * 0.322 + 4 * 0.149 + 5 * 0.029 = 2.5

c) E(X^2) = 0^2 * 0.029 + 1^2 * 0.149 + 2^2 * 0.322 + 3^2 * 0.322 + 4^2 * 0.149 + 5^2 * 0.029 = 7.444

= E(X^2) - (E(X))^2

= 7.444 - (2.5)^2 = 1.194

= 1.1

Five males with an X-linked genetic disorder have one child
each. The random variable x is the number of children among the
five who inherit the X-linked genetic disorder. Determine whether
a probability distribution is given. If a probability distribution
is given, find its mean and standard deviation. If a probability
distribution is not given, identify the requirements that are not
satisfied.
x P(x)
0 0.028
1 0.153
2 0.319
3 0.319
4 0.153
5 0.028
Does the table show...

Five males with a particular genetic disorder have one child
each. The random variable x is the number of children among the
five who inherit the genetic disorder. Determine whether the table
describes a probability distribution. If it does, find the mean
and standard deviation.
x
0
1
2
3
4
5
P(x)
0.01160.0116
0.08340.0834
0.23990.2399
0.34520.3452
0.24840.2484
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Find the mean of the random variable x. Select the correct
choice below and, if necessary, fill in the answer box...

Five males with a particular genetic disorder have one child
each. The random variable x is the number of children among the
five who inherit the genetic disorder. Determine whether the table
describes a probability distribution. If it does, find the mean
and standard deviation.
x
0
1
2
3
4
5
P(x)
0.00020.0002
0.00530.0053
0.04500.0450
0.19190.1919
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Find the mean of the random variable x. Select the correct
choice below and, if necessary, fill in the answer box...

Five males with an X-linked genetic disorder have one child
each. The random variable x is the number of children among the
five who inherit the X-linked genetic disorder. Determine whether
a probability distribution is given. If a probability distribution
is given, find its mean and standard deviation. If a probability
distribution is not given, identify the requirements that are not
satisfied.
x
P(x)
0
0.035
1
0.157
2
0.308
3
0.308
4
0.157
5
0.035
Does the table show...

1. Use the given values of n and p to find the minimum usual
value
muμminus−2sigmaσ
and the maximum usual value
muμplus+2sigmaσ.
Round to the nearest hundredth unless otherwise noted.
nequals=10141014;
pequals=0.860.86
Five males with an X-linked genetic disorder have one child
each. The random variable x is the number of children among the
five who inherit the X-linked genetic disorder. Determine whether
a probability distribution is given. If a probability distribution
is given, find its mean and standard deviation....

Five males with an X-linked genetic disorder have one child
each. The random variable x is the number of children among the
five who inherit the X-linked genetic disorder. Determine whether
a probability distribution is given. If a probability distribution
is given, find its mean and standard deviation. If a probability
distribution is not given, identify the requirements that are not
satisfied. x P(x) 0 0.029 1 0.159 2 0.312 3 0.312 4 0.159 5
0.029
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