Question

To determine whether training in a series of workshops on creative thinking increases IQ scores, a total of 70 students are randomly divided into treatment and control groups of 35 each. After two months of training, the sample mean IQ (–X1) for the treatment group equals 110, and the sample mean IQ (–X2) for the control group equals 108. The estimated standard error equals 1.80.

Question:	Steps:	Calculations or Logic:	Answer:
Using t , test the null hypothesis at the .01 level of significance.	What is the research hypothesis?
	What is the null hypothesis?
	Is this a one-tailed or two-tailed test?
	What are the degrees of freedom?
	What is the t critical for .01 significance?
	What is the calculated t?
	Do you accept or reject the null hypothesis?		We reject the null hypothesis because t is greater then the critical value.
If appropriate (because the null hypothesis has been rejected), estimate the standardized effect size, construct a 99 percent confidence interval for the true population mean difference, and interpret these estimates.

Answer 1