An engineer wishes to determine the width of a particular
electronic component. If she knows that the standard deviation is
1.2 mm, how many of these components should she consider to be 90%
sure of knowing the mean will be within ±0.3 mm?
Given that,
standard deviation =s = =1.2
Margin of error = E = 0.3
At 90% confidence level
= 1 - 90%
= 1 - 0.90 =0.10
/2
= 0.05
Z/2
= Z0.05 = 1.645
sample size = n = [Z/2* / E] 2
n = ( 1.645 *1.2 / 0.3 )2
n =44
Sample size = n =44
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