Question

A cruise company would like to estimate the average beer consumption to plan its beer inventory levels on future​ seven-day cruises.​ (The ship certainly​ doesn't want to run out of beer in the middle of the​ ocean!) The average beer consumption over 16 randomly selected​ seven-day cruises was 81,867 bottles with a sample standard deviation of 4,522 bottles. Complete parts a and b below.

a. Construct a 99​% confidence interval to estimate the average beer consumption per cruise. The 99​% confidence interval to estimate the average beer consumption per cruise is from a lower limit of 78,536 bottles to an upper limit of 85,198 bottles. ​(Round to the nearest whole​ numbers.)

b. What assumptions need to be made about this​ population?

A. The only assumption needed is that the population follows the normal probability distribution.

B. The only assumption needed is that the population follows the​ Student's t-distribution.

C. The only assumption needed is that the population size is larger than 30.

D. The only assumption needed is that the population distribution is skewed to one side.

Answer 1

sample mean = 81867

sample standard deviation = 4522

sample size (n) = 16

For, Z Test for mean, the 99% confidence interval is

The lower limit is 78955 bottles

The upper limit is 84779 bottles.

b.

The correct answer is part A.

This is Z test for mean.

A. The only assumption needed is that the population follows Normal probability distribution.