Question

A tyre manufacturer claims that more than 90% of his tyres will last at least 80,000...

A tyre manufacturer claims that more than 90% of his tyres will last at least 80,000 km. In a random sample of 200 tyres, 190 wore out after reaching 80,000 km. Does this evidence support the manufacturer's claim at the 5% level of significance? Use the following six steps to arrive at your conclusion.
Step 1. Statement of the hypotheses H0: HA:
Step 2. Test statistic and the standardised test statistic
Step 3. Level of significance
Step 4. Decision rule
Step 5. Computation
Step 6. Conclusion

Homework Answers

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
A manufacturer of car batteries claims that his product will last at least 4 years on...
A manufacturer of car batteries claims that his product will last at least 4 years on average. A sample of 50 is taken and the mean and standard deviation are found. The test statistic is calculated to be -1.82. Using a 5% significance level, the conclusion would be: There is sufficient evidence for the manufacturer's claim to be considered correct. There is insufficient evidence for the manufacturer's claim to be considered correct. There is sufficient evidence for the manufacturer's claim...
1.A tyre manufacturer produces tyres that have a mean life of 20,000 km when the production...
1.A tyre manufacturer produces tyres that have a mean life of 20,000 km when the production is working properly. Based on past experience, the standard deviation of the life of tyres is 2,800 km. The operations manager stops the production process if there is evidence that the mean life is different from 20,000 km. If you select a random sample of 100 tyres and you are willing to have a 5% level of significance (i.e. risk of committing a Type...
A manufacturer claims that less than 4% of his produced items are defective. In a random...
A manufacturer claims that less than 4% of his produced items are defective. In a random sample of 300 items, 11 were defective. At α=0.05, test the manufacturer claim. Claim H0 Ha Test Statistic= p-value= Result:
A manufacturer claims that the calling range (in feet) of its 900-MHz cordless telephone is greater...
A manufacturer claims that the calling range (in feet) of its 900-MHz cordless telephone is greater than that of its leading competitor. A sample of 11 phones from the manufacturer had a mean range of 1050 feet with a standard deviation of 40 feet. A sample of 18 similar phones from its competitor had a mean range of 1030 feet with a standard deviation of 25 feet. Do the results support the manufacturer's claim? Let µ1 be the true mean...
A manufacturer claims that the calling range (in feet) of its 900-MHz cordless telephone is greater...
A manufacturer claims that the calling range (in feet) of its 900-MHz cordless telephone is greater than that of its leading competitor. A sample of 12 phones from the manufacturer had a mean range of 1150 feet with a standard deviation of 27 feet. A sample of 7 similar phones from its competitor had a mean range of 1100 feet with a standard deviation of 23 feet. Do the results support the manufacturer's claim? Let μ1μ1 be the true mean...
6. A manufacturer claims that a customer will nd no more than 8% defective knee braces...
6. A manufacturer claims that a customer will nd no more than 8% defective knee braces in a large shipment. A customer decides to test this claim after reading an article in the American Journal of Sports Medicine, which discusses the force exerted on a knee brace used for injured athletes and convinces the customer that high quality is essential. A random sample of 200 braces is selected from the shipment, and 28 defectives are found. Test the manufacturer's claim...
A manufacturer claims that the calling range (in feet) of its 900-MHz cordless telephone is greater...
A manufacturer claims that the calling range (in feet) of its 900-MHz cordless telephone is greater than that of its leading competitor. A sample of 19 phones from the manufacturer had a mean range of 1160 feet with a standard deviation of 32 feet. A sample of 11 similar phones from its competitor had a mean range of 1130 feet with a standard deviation of 23 feet. Do the results support the manufacturer's claim? Let μ1 be the true mean...
A manufacturer claims that the calling range (in feet) of its 900-MHz cordless telephone is greater...
A manufacturer claims that the calling range (in feet) of its 900-MHz cordless telephone is greater than that of its leading competitor. A sample of 8 phones from the manufacturer had a mean range of 1300 feet with a standard deviation of 43 feet. A sample of 14 similar phones from its competitor had a mean range of 1280 feet with a standard deviation of 36 feet. Do the results support the manufacturer's claim? Let μ1μ1 be the true mean...
A manufacturer claims that the calling range (in feet) of its 900-MHz cordless telephone is greater...
A manufacturer claims that the calling range (in feet) of its 900-MHz cordless telephone is greater than that of its leading competitor. A sample of 12 phones from the manufacturer had a mean range of 1010 feet with a standard deviation of 23 feet. A sample of 19 similar phones from its competitor had a mean range of 1000 feet with a standard deviation of 34 feet. Do the results support the manufacturer's claim? Let μ1 be the true mean...
A manufacturer claims that the calling range (in feet) of its 900-MHz cordless telephone is greater...
A manufacturer claims that the calling range (in feet) of its 900-MHz cordless telephone is greater than that of its leading competitor. A sample of 1919 phones from the manufacturer had a mean range of 11101110 feet with a standard deviation of 2222 feet. A sample of 1111 similar phones from its competitor had a mean range of 10601060 feet with a standard deviation of 2323 feet. Do the results support the manufacturer's claim? Let μ1μ1 be the true mean...