Required:
Show your complete solution· Write your formula (explicitly) first before actually solving the problem *Clearly define your random variables or events.
Given the item is defective, probability of it being produced by B=0.26
Explanation:
Prior information
Probability of an item produced by Machine A P(A)=50%=0.5
Probability of an item produced by Machine B P(B)=30%=0.3
Probability of an item produced by Machine C P(C)=20%=0.2
On the basis of additional information
Given the item produced by A, probability of it being defective
P(D/A)=3%=0.03
Given the item produced by B, probability of it being defective
P(D/B)=2%=0.02
Given the item produced by C, probability of it being defective
P(D/C)=1%=0.01
Given the item is defective, probability of it being produced by B
P(BD)=P(B)×P(DB)/[P(B)×P(DB)]+[P(A)×P(DA)]+[P(C)×P(DC)]
=0.3×0.02[0.3×0.02]+[0.5×0.03]+[0.2×0.01]
0.0060.006+0.015+0.002=0.0060.023=0.26
Given the item is defective, probability of it being produced by B=0.26
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