Six different colored dice are rolled. Of interest is the number of dice that show a "3." (D) On average, how many dice would you expect to show a "3"? (E) Find the probability that all six dice show a "3." (Round your answer to five decimal places.) (F) Is it more likely that three or that four dice will show a "3"?
Given data:
6 different coloured dice are rolled.
n = 6
Of interest is the number of dice that show a "3"
p = 3/6 = 1/2
To calculate:
D) On average, how many dice would you expect to show a "3"?
(E) Find the probability that all six dice show a "3."
(F) Is it more likely that three or that four dice will show a "3"?
Now,
D) Out of 6 dice, 6 dice shows 3
So Average = E(x) = n × p
= 6 × 1/2
= 3
Therefore on average 3 dice would expect to show a "3"
E) The probability that all 6 dice shows a "3"
P = (3/6) 6 = (1/2) 6 = 0.01562
Therefore the probability that all 6 dice shows a "3" is 0.01562
F) Half of the 6 dice shows "3" .
So 6/2 = 3
Therefore 3 dice are more likely to show a "3"
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