Question

A tour bus normally leaves for its destination at 5:00 pm for a 270 mile trip....

A tour bus normally leaves for its destination at 5:00 pm for a 270 mile trip. This week however, the bus leaves at 5:30 pm. To arrive on time, the driver drives 6 miles per hour faster than usual. What is the bus' usual speed?

Math   Statistics-And-Probability   
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Answer #1

In general

distance = 270 mile

time = t hours

speed = s miles per hour

if he was 30 minutes late

Today

distance = 270 mile

time = t - 1/2 = t - 0.5 hours

speed = s + 6 miles per hour

Solving the quadratic equation

Since speed can not be negative

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