A tour bus normally leaves for its destination at 5:00 pm for a 270 mile trip. This week however, the bus leaves at 5:30 pm. To arrive on time, the driver drives 6 miles per hour faster than usual. What is the bus' usual speed?
In general
distance = 270 mile
time = t hours
speed = s miles per hour
if he was 30 minutes late
Today
distance = 270 mile
time = t - 1/2 = t - 0.5 hours
speed = s + 6 miles per hour
Solving the quadratic equation
Since speed can not be negative
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