Question

In a game of Texas Hold ’em poker you have a two of hearts and a six of spades. Your opponent has a 4 of clubs and a ten of clubs. The flop shows 3 of clubs, queen of clubs, and jack of diamonds. There are two cards left. Is it more likely you get a straight, or your opponent gets a flush, and what is the chance of each?

Answer 1

since we know , there are 52 cards in a pack

PLAYER 1 : 2 H, 6 S

PLAYER 2 : 4 C, 10 C

FLOP ; 3 C, Q C, J D

7 cards are out on table out of 52, we are left with 45,

P ( player 1 getting a straight in next two deals, i.e. 3 & 4 ) = (6/45) * (3/44) = 0.0091 (since, there are three 3s and three 4s left in the deck)

P( player 2 getting a flush in next two deals, i.e. 2 cards of clubs ) = (9/45) * (8/44) = 0.0364 (since, there are 9 cards left in the deck of clubs)

the opponent is most likely to get a FLUSH