The probability of a manufacturing defect in an aluminum beverage can is .00008 if 100,600 cans are produced find the following
a) at least 7 defective cars
b) at least 8 defective cars
Given :
p = 0.00008
n = 100,600
X : number of defect beverage can
To calculate :
1) the probability of at least 7 defective cars
2) the probability of at least 8 defective cars
Here we use the Poisson approximation binomial distribution.
Therefore a) the probability of at least 7 defective cars is 0.5537
b) the probability of at least 8 defective cars is 0.4142
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