Question

A particular fruit's weights are normally distributed, with a mean of 710 grams and a standard deviation of 6 grams. If you pick one fruit at random, what is the probability that it will weigh between 696 grams and 726 grams

Answer 1

x=particular fruit's weights

x~Normal(=710,=6)

Probability that fruit weights is between 696 and 726 grams = p(696<x<726)= p(x<726)-p(x<696)

Normal distribution, mean() = 710 , stad. Deviation() =6

So p = p((x-)/< (696-710 )/6) -p((x-)/< (726-710 )/6)

= p(z<-2.33) - p(z<2.67) = 0.9962 - 0.0098 = 0.9864

#probability that it will weigh between 696 grams and 726 grams=0.9864