In a certain distribution, the mean is 100 with a standard deviation of 4. Use Chebyshev's Theorem to tell the probability that a number lies between 92 and 108
The probability a number lies between
92
and
108
is at least
Answer:
(Upper - ) / = (108 - 100) / 4 = 2
( - lower) / = (100 - 92) / 4 = 2
In this case k = 2 , the probability that X is within 4 standard deviations of the mean at least
Pr(|X - | < k) 1 - 1/k2
Pr(92 < X < 108) 1 - 1/22
= 4 - 1 /4
= 3/4
= 0.75
Probability = 0.75
NOTE:: I HOPE YOUR HAPPY WITH MY ANSWER....***PLEASE SUPPORT ME WITH YOUR RATING...
***PLEASE GIVE ME "LIKE"...ITS VERY IMPORTANT FOR ME NOW....PLEASE SUPPORT ME ....THANK YOU
Get Answers For Free
Most questions answered within 1 hours.