Question

A nutritionist claims that the mean tuna consumption by a person is 3.9 pounds per year. A sample of 50 people shows that the mean tuna consumption by a person is 3.5 pounds per year. Assume the population standard deviation is 1.05 pounds. At alphaα=0.03​,can you reject the​ claim?

Answer 1

this is the two tailed test .  

The null and alternative hypothesis is ,

H0 :   = 3.9

Ha :     3.9

Test statistic = z

= ( - ) / / n

= (3.5-3.9) / 1.05 / 50

=-2.69

P(z <-2.69 ) = 0.0036 using z table

P-value = 2*0.0036=0.0072

= 0.03

P-value <

Reject the null hypothesis .