You conducted an independent samples t-test to determine whether there is a difference in productivity between employees who work 5-days per week versus 4-days per week. You find the average units produced for the 5-day work week is 26.6 and the average units produced for the 4-day work week is 24.4. Your standard error (of the differences) is 1.48. Using degrees of freedom of 18 and an alpha of .01, construct a 99% confidence interval.
t critical value at 0.01 significance level with 18 df = 2.878
99% confidence interval for is
(1 - 2) - t * SE < < (1 - 2) + t * SE
(26.6 - 24.4 ) - 2.878 * 1.48 < 1 - 2 < (26.6 - 24.4 ) + 2.878 * 1.48
-2.06 < 1 - 2 < 6.46
99% CI is ( -2.06 , 6.46 )
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