For a Normal distribution with mean, μ=2, and standard
deviation, σ=4,
10% of observations have a value less than Round to 4 decimal
places.
10% of observations have a value greater than Round to 4 decimal
places.
Given,
= 2 , = 4
a)
We have to calculate x such that P( X < x) = 0.10
That is 10th percentile = ?
10th percentile = + Z *
= 2 + (-1.2816) * 4
= -3.1264
b)
We have to calculate x such that P( X > x) = 0.10
P( X < x) = 0.90
That is 90th percentile = ?
90th percentile = + Z *
= 2 + (1.2816) * 4
= 7.1264
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