Research has shown the 30% of all houses ( p = 0.3) have faulty wiring. An inspection was done of 18 houses.
Find the probability that four (4) houses have faulty wiring.
Probability that at least 1 house has faulty wiring.
Find the mean and standard deviation.
Let X denotes the number of houses that have faulty wiring in a random sample of 18 houses.
X ~ Binomial(n = 18, p = 0.3)
The probability mass function of X is
Now,
The probability that four (4) houses have faulty wiring
The probability that at least 1 house has faulty wiring
The mean is E(X) = n*p = 18*0.3 = 5.4
The standard deviation is
Get Answers For Free
Most questions answered within 1 hours.