Question

It is estimated that 0.56 percent of the callers to the Customer Service department of Dell...

It is estimated that 0.56 percent of the callers to the Customer Service department of Dell Inc. will receive a busy signal. What is the probability that of today's 1,400 callers at least 5 received a busy signal?

Math   Statistics-And-Probability   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

Here we have given that 0.56 percent of the callers to the Customer Service department of Dell Inc. will receive a busy signal. Therefore p=0.56

Now let total number of callers equal to n=1400 and we have to obtain probability that at least 5 received a busy signal.

Since the distribution of the Customer Service department of Dell Inc. will receive a busy signal is binomial with n=1400 and p=0.56

Let X denote Customer Service department of Dell Inc. will receive a busy signal

Therefore

P(X≥5)= probability that of today's 1,400 callers at least 5 received a busy signal

=1-P(X<5)=1

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
It is estimated that 0.48 percent of the callers to the Customer Service department of Dell...
It is estimated that 0.48 percent of the callers to the Customer Service department of Dell Inc. will receive a busy signal. What is the probability that of today's 1,000 callers at least 5 received a busy signal?
It is estimated that 0.3% of the callers to the billing department of a local telephone...
It is estimated that 0.3% of the callers to the billing department of a local telephone company will receive a busy signal. What is the probability that of today's 1150 callers at least 5 received a busy signal? Use the poisson approximation to the binomial. (Round the final answer to 4 decimal places.) Probability             
The customer service department for a wholesale electronics outlet claims that 80 percent of all customer...
The customer service department for a wholesale electronics outlet claims that 80 percent of all customer complaints are resolved to the satisfaction of the customer. In order to test this claim, a random sample of 15 customers who have filed complaints is selected. (b) Find each of the following if we assume that the claim is true: (Do not round intermediate calculations. Round final answers to 4 decimal places.)   1.   P(x ≤ 13)   2.   P(x > 10)   3.   P(x ≥...
The Customer Service Center in a large New York department store has determined that the amount...
The Customer Service Center in a large New York department store has determined that the amount of time spent with a customer about a complaint is normally distributed, with a mean of 8.3 minutes and a standard deviation of 2.0 minutes. What is the probability that for a randomly chosen customer with a complaint, the amount of time spent resolving the complaint will be as follows. (Round your answers to four decimal places.) (a) less than 10 minutes (b) longer...
The Customer Service Center in a large New York department store has determined that the amount...
The Customer Service Center in a large New York department store has determined that the amount of time spent with a customer about a complaint is normally distributed, with a mean of 9.1 minutes and a standard deviation of 2.3 minutes. What is the probability that for a randomly chosen customer with a complaint, the amount of time spent resolving the complaint will be as follows. (Round your answers to four decimal places.) (a) less than 10 minutes (b) longer...
The Customer Service Center in a large New York department store has determined that the amount...
The Customer Service Center in a large New York department store has determined that the amount of time spent with a customer about a complaint is normally distributed, with a mean of 9.5 minutes and a standard deviation of 2.4 minutes. What is the probability that for a randomly chosen customer with a complaint, the amount of time spent resolving the complaint will be as follows. (Round your answers to four decimal places.) (a) less than 10 minutes (b) longer...
The Customer Service Center in a large New York department store has determined that the amount...
The Customer Service Center in a large New York department store has determined that the amount of time spent with a customer about a complaint is normally distributed, with a mean of 9.1 minutes and a standard deviation of 2.9 minutes. What is the probability that for a randomly chosen customer with a complaint, the amount of time spent resolving the complaint will be as follows. (Round your answers to four decimal places.) (a) less than 10 minutes (b) longer...
The Customer Service Center in a large New York department store has determined that the amount...
The Customer Service Center in a large New York department store has determined that the amount of time spent with a customer about a complaint is normally distributed, with a mean of 8.7 minutes and a standard deviation of 2.0 minutes. What is the probability that for a randomly chosen customer with a complaint, the amount of time spent resolving the complaint will be as follows. (Round your answers to four decimal places.) (a) less than 10 minutes (b) longer...
The Customer Service Center in a large New York department store has determined that the amount...
The Customer Service Center in a large New York department store has determined that the amount of time spent with a customer about a complaint is normally distributed, with a mean of 9.7 minutes and a standard deviation of 2.1 minutes. What is the probability that for a randomly chosen customer with a complaint, the amount of time spent resolving the complaint will be as follows. (Round your answers to four decimal places.) (a) less than 10 minutes (b) longer...
The Customer Service Center in a large New York department store has determined that the amount...
The Customer Service Center in a large New York department store has determined that the amount of time spent with a customer about a complaint is normally distributed, with a mean of 9.3 minutes and a standard deviation of 2.6 minutes. What is the probability that for a randomly chosen customer with a complaint, the amount of time spent resolving the complaint will be as follows. (Round your answers to four decimal places.) (a) less than 10 minutes (b) longer...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT