# of Available Toppings | # of Different Pizzas |
---|---|
0 | 1 |
1 | 2 |
2 | |
3 | |
4 | |
5 | |
6 | |
7 | |
8 |
Question 1
Here is the completed table.
As for each pizza choices we may choose to use none, some or all availble toppings.
so here possible type of pizzas when there are n toppings are
= No toppings + 1 topping + 2 topping + 3 topping
= nC0 + nC1 + nC2 + nC3 + ...nCn =2n
# of Available Toppings | # of Different Pizzas |
0 | 1 |
1 | 2 |
2 | 4 |
3 | 8 |
4 | 16 |
5 | 32 |
6 | 64 |
7 | 128 |
8 | 256 |
(c) Here 2n is exponetial function. We can justify it by graph here.
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