Question

Calculate a 90% confidence interval for the true proportion: True: 20 False: 8 Total: 28

Calculate a 90% confidence interval for the true proportion:
True: 20
False: 8
Total: 28

Homework Answers

Answer #1

Solution :

Given that,

n = 238

x = 20

= x / n = 20 / 28 = 0.714

1 - = 1 - 0.714 = 0.286

At 90% confidence level the z is ,

= 1 - 90% = 1 - 0.90 = 0.10

/ 2 = 0.10 / 2 = 0.05

Z/2 = Z0.05 = 1.645

Margin of error = E = Z / 2 * (( * (1 - )) / n)

= 1.645 * (((0.714 * 0.286) / 28)

= 0.140

A 90% confidence interval for population proportion p is ,

- E < P < + E

0.714 - 0.140 < p < 0.714 + 0.140

0.574 < p < 0.854

(0.574 , 0.854)

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
True or False? To reduce the length of a confidence interval of the population proportion, we...
True or False? To reduce the length of a confidence interval of the population proportion, we can either increase the sample size or decrease the confidence level.
A 90% confidence interval is calculated for the true proportion, p, of all medical students who...
A 90% confidence interval is calculated for the true proportion, p, of all medical students who plan to work in a rural community. The confidence interval is 0.2<p<0.6. Write the interpretation for this confidence interval.
A newsgroup is interested in constructing a 90% confidence interval for the proportion of all Americans...
A newsgroup is interested in constructing a 90% confidence interval for the proportion of all Americans who are in favor of a new Green initiative. Of the 558 randomly selected Americans surveyed, 379 were in favor of the initiative. Round answers to 4 decimal places where possible. a. With 90% confidence the proportion of all Americans who favor the new Green initiative is between and . b. If many groups of 558 randomly selected Americans were surveyed, then a different...
You are interested in constructing a 90% confidence interval for the proportion of all caterpillars that...
You are interested in constructing a 90% confidence interval for the proportion of all caterpillars that eventually become butterflies. Of the 439 randomly selected caterpillars observed, 45 lived to become butterflies. Round answers to 4 decimal places where possible. a. With 90% confidence the proportion of all caterpillars that lived to become a butterfly is between  and . b. If many groups of 439 randomly selected caterpillars were observed, then a different confidence interval would be produced from each group. About  percent...
A newsgroup is interested in constructing a 90% confidence interval for the proportion of all Americans...
A newsgroup is interested in constructing a 90% confidence interval for the proportion of all Americans who are in favor of a new Green initiative. Of the 573 randomly selected Americans surveyed, 369 were in favor of the initiative. Round answers to 4 decimal places where possible. a. With 90% confidence the proportion of all Americans who favor the new Green initiative is between___and___ . b. If many groups of 573 randomly selected Americans were surveyed, then a different confidence...
A 90% confidence interval for the proportion of coffee drinkers that add sugar and creme has...
A 90% confidence interval for the proportion of coffee drinkers that add sugar and creme has results in the following output: one sample proportion summary confidence interval: p: proportion of success method:standard-wald 90% confidence interval results: proportion: p count:1136 total:1803 sample prop: 0.63006101 std. edrr.: 0.011369948 l. limit: 0.61135911 u. limit: 0.6487629 a. Identify the values for n, p, ˆ q, ˆ and E. b. Write a statement that interprets the 90% confidence interval
A smart phone manufacturer is interested in constructing a 90% confidence interval for the proportion of...
A smart phone manufacturer is interested in constructing a 90% confidence interval for the proportion of smart phones that break before the warranty expires. 83 of the 1543 randomly selected smart phones broke before the warranty expired. a. With 90% confidence the proportion of all smart phones that break before the warranty expires is between answer ____ and answer ______. b. If many groups of 1543 randomly selected smart phones are selected, then a different confidence interval would be produced...
A newsgroup is interested in constructing a 90% confidence interval for the proportion of all Americans...
A newsgroup is interested in constructing a 90% confidence interval for the proportion of all Americans who are in favor of a new Green initiative. Of the 577 randomly selected Americans surveyed, 392 were in favor of the initiative. Round answers to 2 decimal places where possible. a. With 90% confidence the proportion of all Americans who favor the new Green initiative is between and . b. If many groups of 577 randomly selected Americans were surveyed, then a different...
A newsgroup is interested in constructing a 90% confidence interval for the proportion of all Americans...
A newsgroup is interested in constructing a 90% confidence interval for the proportion of all Americans who are in favor of a new Green initiative. Of the 543 randomly selected Americans surveyed, 384 were in favor of the initiative. Round answers to 4 decimal places where possible. a. With 90% confidence the proportion of all Americans who favor the new Green initiative is between  and . b. If many groups of 543 randomly selected Americans were surveyed, then a different confidence...
A smart phone manufacturer is interested in constructing a 90% confidence interval for the proportion of...
A smart phone manufacturer is interested in constructing a 90% confidence interval for the proportion of smart phones that break before the warranty expires. 89 of the 1692 randomly selected smart phones broke before the warranty expired. Round answers to 4 decimal places where possible. a. With 90% confidence the proportion of all smart phones that break before the warranty expires is between _______ and _______ . b. If many groups of 1692 randomly selected smart phones are selected, then...