Assume the random variable X has a binomial distribution with the given probability of obtaining a success. Find the following probability, given the number of trials and the probability of obtaining a success. Round your answer to four decimal places. P(X≥16), n=19, p=0.7
Solution:
Given that,
P = 0.7
1 - P = 0.3
n = 19
Here, BIN ( n , P ) that is , BIN (19 , 0.7)
then,
n*p = 13.3 > 5
n(1- P) = 5.7 > 5
According to normal approximation binomial,
X Normal
Mean = = n*P = 13.3
Standard deviation = =n*p*(1-p) = 3.99
We using continuity correction factor
P(X a ) = P(X > a - 0.5)
P(x > 15.5) = 1 - P(x < 15.5)
= 1 - P((x - ) / < (15.5 - 13.3) /3.99 )
= 1 - P(z < 1.10)
= 1 - 0.8643
= 0.1357
Probability = 0.1357
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