Question

You walk up to a vending machine that has a variety of flavored candy in it. If you give it money, it will randomly select a piece for you. 15 blue 10 red 18 orange 7 green

What is the Conditional Probability that you will get 1 piece of orange and one piece of green if both are replaced?

What is the conditional probability to get 3 pieces of blue if none are replaced?

Answer 1

Result:

You walk up to a vending machine that has a variety of flavored candy in it. If you give it money, it will randomly select a piece for you. 15 blue 10 red 18 orange 7 green

What is the Conditional Probability that you will get 1 piece of orange and one piece of green if both are replaced?

Total candies= 15+10+18+7=50

P( orange, then green) = (18/50)*(7/50)

=0.0504

What is the conditional probability to get 3 pieces of blue if none are replaced?

P( blue, then blue, then blue) = (15/50)*(14/49)*(13/48)

=0.023214